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10=-7x+x^2
We move all terms to the left:
10-(-7x+x^2)=0
We get rid of parentheses
-x^2+7x+10=0
We add all the numbers together, and all the variables
-1x^2+7x+10=0
a = -1; b = 7; c = +10;
Δ = b2-4ac
Δ = 72-4·(-1)·10
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{89}}{2*-1}=\frac{-7-\sqrt{89}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{89}}{2*-1}=\frac{-7+\sqrt{89}}{-2} $
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